ArrayAllocationWithoutNew

DRAFT

Correction

Here is what's right.

Arrays are allocated on the heap. They are a special kind of object. To allocate them, one needs to use new in almost all situations. So, to allocate the above array, one needs to write new Integer[3].

char[] a;
a = new char[12];                       // new required
a = new char[] {'A', 'B', 'C'};         // new required

However, there is an exception: initializers in array variable declarations do not need to specify the array type and the new:

char[] a = new char[] {'A', 'B', 'C'};
char[] a =            {'A', 'B', 'C'};  // ok