LargeIntegerLong
A number like 4000000000000, which is too big to fit into a 32-bit signed int,
is interpreted as a literal of type long.
Large integer numbers have type long
Integer numbers without L or l suffix that are too large for an int are illegal
CorrectionHere is what's right.
In Java, large integral literals do not implicitly have type long.
To get a long literal, one needs to add an L or l as a suffix.
The following code would not compile:
long number = 12345678901234; // ERROR: integer number too largeThe following code also would not compile:
long number = (long)12345678901234; // ERROR: integer number too largeThe following tree shows the reason for this compiler error:
(long)12345678901234 is an expression consisting of a cast operator (long)
and its operand, the number 12345678901234.
However, as shown above, that operand is not a legal literal,
and thus the expression will not compile.
Java provides the suffix L or l to allow expressing a long value as a literal:
long number = 12345678901234L; // OK: long literalAs the following tree shows, the literal 12345678901234L is an expression
of type long with value 12345678901234.