EqualityOperatorComparesOnlyTypes

Not Yet Observed

Correction

Here is what's right.

The () = () operator compares the values of its operands.

While the following block, with operands of different types (the first a string, the second a number) evaluate to false

the following block also evaluates to false; the two operands have the same type, they are numbers, but they have different values:

Origin

Where could this misconception come from?

In JavaScript there are different equality operators (== and ===), and the difference in their semantics has something to do with the types of their operands.